这篇文章上次修改于 2173 天前，可能其部分内容已经发生变化，如有疑问可询问作者。 >spring boot自带的json converter和fastjson对scala生成的对象，都不能很好的序列化成json。结果都会为空 解决办法： [1] 需要序列化的类型，用kotlin定义.毕竟kotlin和scala的类定义语法基本相同 [2] 使用或者替换fastjson或者springboot的http message converter.如替换为json4s [3] 附录：spring boot默认的converter如下： * ByteArrayHttpMessageConverter – converts byte arrays * StringHttpMessageConverter – converts Strings * ResourceHttpMessageConverter – converts org.springframework.core.io.Resource for any type of octet stream * SourceHttpMessageConverter – converts javax.xml.transform.Source * FormHttpMessageConverter – converts form data to/from a MultiValueMap<String, String>. * Jaxb2RootElementHttpMessageConverter – converts Java objects to/from XML (added only if JAXB2 is present on the classpath) * MappingJackson2HttpMessageConverter – converts JSON (added only if Jackson 2 is present on the classpath) * MappingJacksonHttpMessageConverter – converts JSON (added only if Jackson is present on the classpath) * AtomFeedHttpMessageConverter – converts Atom feeds (added only if Rome is present on the classpath) * RssChannelHttpMessageConverter – converts RSS feeds (added only if Rome is present on the classpath)
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